`{ab(a-b)(a-c)} / {ac(b-a)(b-c)}`
They both share a on the top and bottom you should first divide by a to cancel out a, that would leave you:
`(b(a-b)(a-c)) / (c(b-a)(b-c))`
Now switch the order of b-a to -a+b,
`(b(a-b)(a-c))/ (c(-a+b)(b-c))`
Now factor out a negative to make the denominator and the nominator the same:
`(b(a-b)(a-c))/ (-c(a-b)(b-c))`
now divide by a-b to cancel them out
you should be left over with:
`(b(a-c))/(-c(b-c))`
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