Formula of arithmetic progression of the nth term would be:
an=a1+(n-1)s
where a1: the initial term of an arithmetic progression
s: common difference of successive numbers
You know the third term is 8 so:
8= a1+(3-1)s
8=a1+2s
You know that the seventh term is 20 so:
20= a1+(7-1)s - eqn 1
20=a1+6s - eqn 2
Subtract eqn 1 from eqn 2
20-8=a1-a1+6s-2s
12=4s
4s=12
s=3//
So, use this value and substitute into eqn 2
20= a1+6(3)
a1+18=20
a1=20-18
a1=2//
The first term would be 2
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