Wednesday, February 5, 2014

Help with this inequation! x^2 - 4x -12>0

First of all, find the values of x (there are 2 because of the grade of inequation) for the inequation is annulled. For this reason, we transform the above inequation into an equation.


x^2 -4x -12 = 0


After that, forf finding the roots of the equation, we are using the following formula:


X1=[-b + (b^2 - 4ac)^1/2]/2a, where a=1, b=-4, c =-12


a,b,c being the coefficients of the equation above.


X2= [-b - (b^2 - 4ac)^1/2]/2a


after calculation


X1=6, X2=-2


After that, following the rule which says that between the two roots, the values of x have the opposite sign of the "a" coefficient, and outside the roots, the values of X have the same sign with the coefficient "a", we could find the conclusion that inequation is positive on the following intervals


(-ininite, -2) U (6, + infinite)

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