For a linear function f, f(-1)=3 and f(2)=4 find an equation for fplease answer soon, I need help badly

The general form of a linear function is

f(x)=ax + b

So, f(-1)=3 means that we hhave to substitute, in the general form, the unknown x with the value -1.

-1xa + b = 3

We'll do the  same thing with the following f(2)=4

2a +b = 4

Now, in order to find the function f, we have to determine the unknown coefficients a and b.

SO, we'll subtract from the last relation, 2a +b = 4, the anterior one ,-a + b= 3.

2a +b - (-a) +b = 4-3

3a = 1

a = 1/3

With the known value of a, we are going in any of the both anterior relation, substitute a and find out the value of b unknown.

We choose the relation -a + b =3, beccause it's more simple to calculate b, after substituting a value.

-1/3 + b = 3

b = 3 + 1/3

The common denominator is 3, so we have to multiply the first term 3, with the common denominator 3

b = ( 9 +1)/3

b = 10/3

Now we could write down the linear function f.

f(x) = (1/3)x + 10/3