What is the solution for in and out table, 1 in 2 out, 2 in 4 out, 3 in 7 out, 4 in ? out, 5 in and ? out.

In          1          2       3          4         5

out         2         4       7           --       --

From the above pattern we observe that every successive out term is a sum of  previous out+current In.

i.e.       the secon out 4= first out 2+second In 2

           the third out 7= second out 4+third in 3

          the fourth out =third out 7+ fourth In 4

                                =11

            the fifth out= fourth out 11+ fifth In 5

                              =16.

So,      the numbers are    11 and 16.